Re: [HTCondor-users] $(PROCESS) - enumerate it?

[lejeczek <peljasz@xxxxxxxxxxx>]

On 19/09/17 18:48, John M Knoeller wrote:
> you can do this, but due to some limitations in the parser for the $() expansion stuff, you have to use a temporary variable.
>
> Add this to your submit file
>
>    OutputId = $(Process)+1
>    output = $INT(OutputId)
>
> Note that Process is an alias for ProcId.  They both evaluate to the same thing, but ProcId is the actual attribute name that you see when you use condor_q -long. so the preferred form is this
>
>    OutputId = $(ProcId)+1
>    output = $INT(OutputId)
>
> the $INT() macro expansion has an optional second argument that you can use to control the formatting, the main use for this is to get leading zeros.  for instance this:
>
>    tmp = $(ProcId)+1
>    output = $INT(tmp,%04d)
>
> will produce the sequence 0001, 0002, 0003, etc
>
> But leading an trailing characters in the formatting are honored, so this
>
>    tmp = $(ProcId)+1
>    output = $INT(tmp,file_%04d)
>
> will produce the sequence file_0001, file_0002, file_0003, etc
>
> -tj

thanks a lot! btw, should not something like processes ids 
start from 1 anyway?
I mean, to an amateur like myself even the sound of "first 
process having number zero" does not vibrate right.

> -----Original Message-----
> From: HTCondor-users [mailto:htcondor-users-bounces@xxxxxxxxxxx] On Behalf Of lejeczek
> Sent: Tuesday, September 19, 2017 6:34 AM
> To: HTCondor Users Mailinglist <htcondor-users@xxxxxxxxxxx>
> Subject: [HTCondor-users] $(PROCESS) - enumerate it?
>
> hi all
>
> I'm reading docs on macros and I wonder(for I've not across
> yes) how to make something like: output = $(PROCESS)+1.
>
> Simple thought here I had was how to start enumerate from 1
> since very rarely in my setups anything would start with 0.
>
> many thanks,
> p.s. beginner here, so go easy on me.
>
>
> .
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